Free SAP C_ABAPD_2309 Exam 2024 Practice Materials Collection [Q14-Q33]

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Free SAP C_ABAPD_2309 Exam 2024 Practice Materials Collection

C_ABAPD_2309 Exam Info and Free Practice Test All-in-One Exam Guide May-2024

NEW QUESTION # 14
What would be the correct expression to change a given string value 'mr joe doe' into 'JOE' in an ABAP SQL field list?

  • A. SELECT FROM TABLE dbtabl FIELDS
    Of1,
    substring(lower(upper( 'mr joe doe' ) ), 4, 3) AS f2_sub_lo_up, f3,
  • B. SELECT FROM TABLE dbtabl FIELDS
    Of1,
    upper(left( 'mr joe doe', 6)) AS f2_up_left, f3,
  • C. SELECT FROM TABLE dbtabl FIELDS
    Of1,
    substring(upper('mr joe doe'), 4, 3) AS f2_sub_up, f3,...
  • D. SELECT FROM TABLE dbtabl FIELDS
    Of1,
    left(lower(substring( 'mr joe doe', 4, 3)), 3) AS f2_left_lo_sub, f3,

Answer: C

Explanation:
The correct expression to change a given string value 'mr joe doe' into 'JOE' in an ABAP SQL field list is C. SELECT FROM TABLE dbtabl FIELDS Of1, substring(upper('mr joe doe'), 4, 3) AS f2_sub_up, f3,... This expression uses the following SQL functions for strings12:
upper: This function converts all lowercase characters in a string to uppercase. For example, upper('mr joe doe') returns 'MR JOE DOE'.
substring: This function returns a substring of a given string starting from a specified position and with a specified length. For example, substring('MR JOE DOE', 4, 3) returns 'JOE'.
AS: This keyword assigns an alias or a temporary name to a field or an expression in the field list. For example, AS f2_sub_up assigns the name f2_sub_up to the expression substring(upper('mr joe doe'), 4, 3).
You cannot do any of the following:
A) SELECT FROM TABLE dbtabl FIELDS Of1, upper(left( 'mr joe doe', 6)) AS f2_up_left, f3,...: This expression uses the wrong SQL function for strings to get the desired result. The left function returns the leftmost characters of a string with a specified length, ignoring the trailing blanks. For example, left( 'mr joe doe', 6) returns 'mr joe'. Applying the upper function to this result returns 'MR JOE', which is not the same as 'JOE'.
B) SELECT FROM TABLE dbtabl FIELDS Of1, left(lower(substring( 'mr joe doe', 4, 3)), 3) AS f2_left_lo_sub, f3,...: This expression uses unnecessary and incorrect SQL functions for strings to get the desired result. The lower function converts all uppercase characters in a string to lowercase. For example, lower(substring( 'mr joe doe', 4, 3)) returns 'joe'. Applying the left function to this result with the same length returns 'joe' again, which is not the same as 'JOE'.
D) SELECT FROM TABLE dbtabl FIELDS Of1, substring(lower(upper( 'mr joe doe' ) ), 4, 3) AS f2_sub_lo_up, f3,...: This expression uses unnecessary and incorrect SQL functions for strings to get the desired result. The lower function converts all uppercase characters in a string to lowercase, and the upper function converts all lowercase characters in a string to uppercase. Applying both functions to the same string cancels out the effect of each other and returns the original string. For example, lower(upper( 'mr joe doe' ) ) returns 'mr joe doe'. Applying the substring function to this result returns 'joe', which is not the same as 'JOE'.


NEW QUESTION # 15
Given the following Core Data Service View Entity Data Definition:
1 @AccessControl.authorizationCheck: #NOT_REQUIRED
2 DEFINE VIEW ENTITY demo_flight_info_join
3 AS SELECT
4 FROM scarr AS a
5 LEFT OUTER JOIN scounter AS c
6 LEFT OUTER JOIN sairport AS p
7 ON p.id = c.airport
8 ON a.carrid = c.carrid
9 {
10 a.carridAS carrier_id,
11 p.idAS airport_id,
12 c.countnumAS counter_number
13 }
In what order will the join statements be executed?

  • A. sairport will be joined to scounter first and the result will be joined with scarr.
  • B. scarr will be joined with sairport first and the result will be joined with scounter.
  • C. scarr will be joined with scounter first and the result will be joined with sairport.
  • D. scounter will be joined to sairport first and the result will be joined with scarr.

Answer: C

Explanation:
Explanation
The order in which the join statements will be executed is:
scarr will be joined with scounter first and the result will be joined with sairport.
This is because the join statements are nested from left to right, meaning that the leftmost data source is joined with the next data source, and the result is joined with the next data source, and so on. The join condition for each pair of data sources is specified by the ON clause that follows the data source name. The join type for each pair of data sources is specified by the join operator that precedes the data source name. In this case, the join operator is LEFT OUTER JOIN, which means that all the rows from the left data source are included in the result, and only the matching rows from the right data source are included. If there is no matching row from the right data source, the corresponding fields are filled with initial values1.
Therefore, the join statements will be executed as follows:
First, scarr AS a will be joined with scounter AS c using the join condition a.carrid = c.carrid. This means that all the rows from scarr will be included in the result, and only the rows from scounter that have the same value for the carrid field will be included. If there is no matching row from scounter, the countnum field will be filled with an initial value.
Second, the result of the first join will be joined with sairport AS p using the join condition p.id = c.airport. This means that all the rows from the first join will be included in the result, and only the rows from sairport that have the same value for the id field as the airport field from the first join will be included. If there is no matching row from sairport, the id field will be filled with an initial value.
References: 1: Join - ABAP Keyword Documentation


NEW QUESTION # 16
You have two internal tables itab1 and itab2.What is true for using the expression itab1 = corresponding #( itab2 )? Note: There are 2 correct answers to this question.

  • A. itab1 and itab2 must have the same data type.
  • B. itab1 and itab2 must have at least one field name in common.
  • C. Fields with the same name and the same type will be copied from itab2 to itab1.
  • D. Fields with the same name but with different types may be copied from itab2 to itab1.

Answer: B,C

Explanation:
The expression itab1 = corresponding #( itab2 ) is a constructor expression with the component operator CORRESPONDING that assigns the contents of the internal table itab2 to the internal table itab1. The following statements are true for using this expression:
B: itab1 and itab2 must have at least one field name in common. This is because the component operator CORRESPONDING assigns the identically named columns of itab2 to the identically named columns of itab1 by default, according to the rules of MOVE-CORRESPONDING for internal tables. If itab1 and itab2 do not have any field name in common, the expression will not assign any value to itab1 and it will remain initial or unchanged1 C: Fields with the same name and the same type will be copied from itab2 to itab1. This is because the component operator CORRESPONDING assigns the identically named columns of itab2 to the identically named columns of itab1 by default, according to the rules of MOVE-CORRESPONDING for internal tables. If the columns have the same name but different types, the assignment will try to perform a conversion between the types, which may result in a loss of precision, a truncation, or a runtime error, depending on the types involved1 The following statements are false for using this expression:
A: Fields with the same name but with different types may be copied from itab2 to itab1. This is not true, as explained in statement C. The assignment will try to perform a conversion between the types, which may result in a loss of precision, a truncation, or a runtime error, depending on the types involved1 D: itab1 and itab2 must have the same data type. This is not true, as the component operator CORRESPONDING can assign the contents of an internal table of one type to another internal table of a different type, as long as they have at least one field name in common. The target type of the expression is determined by the left-hand side of the assignment, which is itab1 in this case. The expression will create an internal table of the same type as itab1 and assign it to itab11


NEW QUESTION # 17
What RESTful Application Programming feature is used to ensure the uniqueness of a semantic key?

  • A. Determination
  • B. Action
  • C. Validation

Answer: A

Explanation:
Explanation
The RESTful Application Programming feature that is used to ensure the uniqueness of a semantic key is determination. A determination is a type of behavior implementation that defines a logic that is executed automatically when certain events occur, such as create, update, delete, or activate. A determination can be used to calculate or derive values for certain fields, such as semantic keys, based on other fields or external sources. A determination can also be used to check the uniqueness of a semantic key by comparing it with the existing values in the database or the transaction buffer. A determination can use the ABAP SQL or the EML syntax to access and manipulate data. A determination can be defined using the DETERMINE action clause in the behavior definition of a CDS view entity or a projection view. A determination can also be annotated with the @ObjectModel.determination annotation to specify the event, the timing, and the scope of the determination12 The other RESTful Application Programming features are not used to ensure the uniqueness of a semantic key, but have different purposes and effects. These features are:
Validation: A validation is a type of behavior implementation that defines a logic that is executed automatically when certain events occur, such as create, update, delete, or activate. A validation can be used to check the consistency and correctness of the data, such as mandatory fields, data types, value ranges, or business rules. A validation can use the ABAP SQL or the EML syntax to access and manipulate data. A validation can be defined using the VALIDATE action clause in the behavior definition of a CDS view entity or a projection view. A validation can also be annotated with the
@ObjectModel.validation annotation to specify the event, the timing, and the scope of the validation12 Action: An action is a type of behavior implementation that defines a logic that is executed explicitly by the user or the application. An action can be used to perform a specific business operation, such as creating, updating, deleting, or activating an entity instance, or triggering a workflow or a notification.
An action can use the ABAP SQL or the EML syntax to access and manipulate data. An action can be defined using the ACTION clause in the behavior definition of a CDS view entity or a projection view. An action can also be annotated with the @ObjectModel.action annotation to specify the name, the description, the parameters, and the visibility of the action12 References: Behavior Implementation - ABAP Keyword Documentation, Behavior Definition - ABAP Keyword Documentation


NEW QUESTION # 18
Which of the following are features of Core Data Services? Note: There are 3 correct answers to this question.

  • A. Structured Query Language (SQL)
  • B. Inheritance
  • C. Delegation
  • D. Associations
  • E. Annotations

Answer: A,D,E

Explanation:
Explanation
Core Data Services (CDS) is a framework for defining and consuming semantically rich data models in SAP HANA. CDS supports various features that enhance the capabilities of SQL and enable developers to create data models that are optimized for performance, readability, and extensibility12. Some of the features of CDS are:
Associations: Associations are a way of defining relationships between CDS entities, such as tables or views. Associations enable navigation and path expressions in CDS queries, which allow accessing data from related entities without explicit joins. Associations also support cardinality, referential constraints, and cascading options34.
Annotations: Annotations are a way of adding metadata to CDS entities or their elements, such as fields or parameters. Annotations provide additionalinformation or instructions for the CDS compiler, the database, or the consumers of the CDS views. Annotations can be used for various purposes, such as defining access control, UI rendering, OData exposure, or search capabilities5 .
Structured Query Language (SQL): SQL is the standard language for querying and manipulating data in relational databases. CDS is based on SQL and extends it with additional features and syntax. CDS supports SQL features such as joins, aggregations, filters, expressions, functions, and subqueries. CDS also supports SQL Script, which is a scripting language for stored procedures and functions in SAP HANA .
You cannot do any of the following:
Inheritance: Inheritance is not a feature of CDS. Inheritance is a concept in object-oriented programming that allows a class to inherit the properties and methods of another class. CDS does not support object-oriented programming or classes.
Delegation: Delegation is not a feature of CDS. Delegation is a concept in object-oriented programming that allows an object to delegate some of its responsibilities to another object. CDS does not support object-oriented programming or objects.
References: 1: Core Data Services (CDS) | CAPire 2: Core Data Services [CDS] in SAP S/4 HANA | SAP Blogs 3: Associations in Core Data Services (CDS) | SAP Help Portal 4: [CDS DDL - Association - ABAP Keyword Documentation - SAP Online Help] 5: [Annotations in Core Data Services (CDS) | SAP Help Portal]
[CDS DDL - Annotation - ABAP Keyword Documentation - SAP Online Help] : [Structured Query Language (SQL) | SAP Help Portal] : [CDS DDL - SQL Features - ABAP Keyword Documentation - SAP Online Help] : [Object-Oriented Programming in ABAP | SAP Help Portal]


NEW QUESTION # 19
What are some characteristics of secondary keys for internal tables? Note: There are 3 correct answers to this question.

  • A. Multiple secondary keys are allowed for any kind of internal table.
  • B. Secondary keys must be chosen explicitly when you actually read from an internal table.
  • C. Secondary keys can only be created for standard tables.
  • D. Hashed secondary keys do NOT have to be unique.
  • E. Sorted secondary keys do NOT have to be unique.

Answer: A,B,E

Explanation:
Explanation
Secondary keys are additional keys that can be defined for internal tables to optimize the access to the table using fields that are not part of the primary key. Secondary keys can be either sorted or hashed, depending on the table type and the uniqueness of the key. Secondary keys have the following characteristics1:
A). Secondary keys must be chosen explicitly when you actually read from an internal table. This means that when you use a READ TABLE or a LOOP AT statement to access an internal table, you have to specify the secondary key that you want to use with the USING KEY addition. For example, the following statement reads an internal table itab using a secondary key sec_key:
READ TABLE itab USING KEY sec_key INTO DATA(wa).
If you do not specify the secondary key, the system will use the primary key by default2.
B). Multiple secondary keys are allowed for any kind of internal table. This means that you can define more than one secondary key for an internal table, regardless of the table type. For example, the following statement defines an internal table itab with two secondary keys sec_key_1 and sec_key_2:
DATA itab TYPE SORTED TABLE OF ty_itab WITH NON-UNIQUE KEY sec_key_1 COMPONENTS field1 field2 sec_key_2 COMPONENTS field3 field4.
You can then choose which secondary key to use when you access the internal table1.
D). Sorted secondary keys do NOT have to be unique. This means that you can define a sorted secondary key for an internal table that allows duplicate values for the key fields. A sorted secondary key maintains a predefined sorting order for the internal table, which is defined by the key fields in the order in which they are specified. For example, the following statement defines a sorted secondary key sec_key for an internal table itab that sorts the table by field1 in ascending order and field2 in descending order:
DATA itab TYPE STANDARD TABLE OF ty_itab WITH NON-UNIQUE SORTED KEY sec_key COMPONENTS field1 ASCENDING field2 DESCENDING.
You can then access the internal table using the sorted secondary key with a binary search algorithm, which is faster than a linear search3.
The following are not characteristics of secondary keys for internal tables, because:
C). Hashed secondary keys do NOT have to be unique. This is false because hashed secondary keys must be unique. This means that you can only define a hashed secondary key for an internal table that does not allow duplicate values for the key fields. A hashed secondary key does not have a predefined sorting order for the internal table, but uses a hash algorithm to store and access the table rows. For example, the following statement defines a hashed secondary key sec_key for an internal table itab that hashes the table by field1 and field2:
DATA itab TYPE STANDARD TABLE OF ty_itab WITH UNIQUE HASHED KEY sec_key COMPONENTS field1 field2.
You can then access the internal table using the hashed secondary key with a direct access algorithm, which is very fast.
E). Secondary keys can only be created for standard tables. This is false because secondary keys can be created for any kind of internal table, such as standard tables, sorted tables, and hashed tables. However, the type of the secondary key depends on the type of the internal table. For example, a standard table can have sorted or hashed secondary keys, a sorted table can have sorted secondary keys, and a hashed table can have hashed secondary keys1.
References: 1: Secondary Table Key - ABAP Keyword Documentation 2: READ TABLE - ABAP Keyword Documentation 3: Sorted Tables - ABAP Keyword Documentation : Hashed Tables - ABAP Keyword Documentation


NEW QUESTION # 20
Refer to the Exhibit.

The "demo_ods_assoc_spfi data source referenced in line #4 contains a field "connid" which you would like to expose in the element list.
Which of the following statements would do this if inserted on line #8?

  • A. spfli-connid,
  • B. _spfli.connid/
  • C. demo_ods_assoc_spfli-connid/
  • D. demo_ods_assoc_spfli.connid,

Answer: D

Explanation:
The statement that can be used to expose the field "connid" of the data source "demo_ods_assoc_spfli" in the element list is A. demo_ods_assoc_spfli.connid,. This statement uses the dot notation to access the field "connid" of the data source "demo_ods_assoc_spfli", which is an association defined on line #4. The association "demo_ods_assoc_spfli" links the data source "demo_ods" with the table "spfli" using the field "carrid". The statement also ends with a comma to separate it from the next element in the list12.
You cannot do any of the following:
B) demo_ods_assoc_spfli-connid/: This statement uses the wrong syntax to access the field "connid" of the data source "demo_ods_assoc_spfli". The dash notation is used to access the components of a structure or a table, not the fields of a data source. The statement also ends with a slash, which is not a valid separator for the element list12.
C) spfli-connid,: This statement uses the wrong data source name to access the field "connid". The data source name should be "demo_ods_assoc_spfli", not "spfli". The statement also uses the wrong syntax to access the field "connid", as explained above12.
D) _spfli.connid/: This statement uses the wrong data source name and the wrong separator to access the field "connid". The data source name should be "demo_ods_assoc_spfli", not "_spfli". The statement also ends with a slash, which is not a valid separator for the element list12.


NEW QUESTION # 21
Exhibit:

With Icl_super being superclass for Icl_subl and Icl_sub2 and with methods subl_methl and sub2_methl being subclass-specific methods of Id_subl or Icl_sub2, respectivel. What will happen when executing these casts?
Note:
There are 2 correct answers to this question

  • A. go_sub2 = CAST #(go_super). will not work. ] go sub2->sub2 meth 1(...). will work
  • B. go_subl->subl_meth !(...)* w'll work.
  • C. go_sub2 = CAST # go super), will work. go_subl CAST #go_super), will work
  • D. go subl = CAST # go super), will not work

Answer: B,D

Explanation:
Explanation
The following are the explanations for each statement:
A: This statement is correct. go_subl = CAST #(go_super) will not work. This is because go_subl is a data object of type REF TO cl_subl, which is a reference to the subclass cl_subl. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_subl, but this is notpossible, as go_super is not pointing to an instance of cl_subl, but to an instance of cl_super. Therefore, the CAST operator will raise an exception CX_SY_MOVE_CAST_ERROR at runtime12 B: This statement is incorrect. go_sub2 = CAST #(go_super) will work. go_subl = CAST #(go_super) will not work. This is because go_sub2 is a data object of type REF TO cl_sub2, which is a reference to the subclass cl_sub2. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_sub2, and this is possible, as go_super is pointing to an instance of cl_sub2, which is a subclass of cl_super.
Therefore, the CAST operator will assign the reference of go_super to go_sub2 without raising an exception. However, the CAST operator will not work for go_subl, as explained in statement A12 C: This statement is incorrect. go_sub2 = CAST #(go_super) will work. go_sub2->sub2_meth1(...) will not work. This is because go_sub2 is a data object of type REF TO cl_sub2, which is a reference to the subclass cl_sub2. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_sub2, and this is possible, as go_super is pointing to an instance of cl_sub2, which is a subclass of cl_super.
Therefore, the CAST operator will assign the reference of go_super to go_sub2 without raising an exception. However, the method call go_sub2->sub2_meth1(...) will not work, as sub2_meth1 is a subclass-specific method of cl_sub2, which is not inherited by cl_super. Therefore, the method call will raise an exception CX_SY_DYN_CALL_ILLEGAL_METHOD at runtime123 D: This statement is correct. go_subl->subl_meth1(...) will work. This is because go_subl is a data object of type REF TO cl_subl, which is a reference to the subclass cl_subl. subl_meth1 is a subclass-specific method of cl_subl, which is not inherited by cl_super. Therefore, the method call go_subl->subl_meth1(...) will work, as go_subl is pointing to an instance of cl_subl, which has the method subl_meth1123 References: NEW - ABAP Keyword Documentation, CAST - ABAP Keyword Documentation, Method Call - ABAP Keyword Documentation


NEW QUESTION # 22
Exhibit:

What are valid statements? Note: There are 3 correct answers to this question.

  • A. go_cll may call method ml with go_dl->ifl-ml().
  • B. Instead of go_cll = NEW #() you could use go_iff - NEW #(...).
  • C. Instead of go ell = NEW #(...) you could use go ifl = NEW cll(. ... ).
  • D. go_if 1 may call method ml with go_ift->ml().
  • E. go_ifl may call method m2 with go if->m2(...).

Answer: C,D,E

Explanation:
The following are the explanations for each statement:
A: This statement is valid. go_ifl may call method ml with go_ifl->ml(). This is because go_ifl is a data object of type REF TO ifl, which is a reference to the interface ifl. The interface ifl defines a method ml, which can be called using the reference variable go_ifl. The class cll implements the interface ifl, which means that it provides an implementation of the method ml. The data object go_ifl is assigned to a new instance of the class cll using the NEW operator and the inline declaration operator @DATA. Therefore, when go_ifl->ml() is called, the implementation of the method ml in the class cll is executed123 B: This statement is valid. Instead of go_cll = NEW #(...) you could use go_ifl = NEW cll(...). This is because go_ifl is a data object of type REF TO ifl, which is a reference to the interface ifl. The class cll implements the interface ifl, which means that it is compatible with the interface ifl. Therefore, go_ifl can be assigned to a new instance of the class cll using the NEW operator and the class name cll. The inline declaration operator @DATA is optional in this case, as go_ifl is already declared. The parentheses after the class name cll can be used to pass parameters to the constructor of the class cll, if any123 E: This statement is valid. go_ifl may call method m2 with go_ifl->m2(...). This is because go_ifl is a data object of type REF TO ifl, which is a reference to the interface ifl. The class cll implements the interface ifl, which means that it inherits all the components of the interface ifl. The class cll also defines a method m2, which is a public method of the class cll. Therefore, go_ifl can call the method m2 using the reference variable go_ifl. The method m2 is not defined in the interface ifl, but it is accessible through the interface ifl, as the interface ifl is implemented by the class cll. The parentheses after the method name m2 can be used to pass parameters to the method m2, if any123 The other statements are not valid, as they have syntax errors or logical errors. These statements are:
C: This statement is not valid. go_cll may call method ml with go_cll->ifl~ml(). This is because go_cll is a data object of type REF TO cll, which is a reference to the class cll. The class cll implements the interface ifl, which means that it inherits all the components of the interface ifl. The interface ifl defines a method ml, which can be called using the reference variable go_cll. However, the syntax for calling an interface method using a class reference is go_cll->ml(), not go_cll->ifl~ml(). The interface component selector ~ is only used when calling an interface method using an interface reference, such as go_ifl->ifl~ml(). Using the interface component selector ~ with a class reference will cause a syntax error123 D: This statement is not valid. Instead of go_cll = NEW #() you could use go_ifl = NEW #(...). This is because go_ifl is a data object of type REF TO ifl, which is a reference to the interface ifl. The interface ifl cannot be instantiated, as it does not have an implementation. Therefore, go_ifl cannot be assigned to a new instance of the interface ifl using the NEW operator and the inline declaration operator @DATA. This will cause a syntax error or a runtime error. To instantiate an interface, you need to use a class that implements the interface, such as the class cll123


NEW QUESTION # 23
Which internal table type allows unique and non-unique keys?

  • A. Hashed
  • B. Sorted
  • C. Standard

Answer: C

Explanation:
Explanation
The internal table type that allows both unique and non-unique keys is the standard table. A standard table has an internal linear index that can be used to access the table entries. The key of a standard table is always non-unique, which means that the table can contain duplicate entries. However, the system does not check the uniqueness of the key when inserting new entries, so the programmer can ensure that the key is unique by using appropriate logic. A standard table can be accessed either by using the table index or the key, but the response time for key access is proportional to the table size.
The other two internal table types, sorted and hashed, do not allow non-unique keys. A sorted table is filled in sorted order according to the defined table key, which must be unique. A sorted table can be accessed either by using the table index or the key, but the response time for key access is logarithmically proportional to the table size. A hashed table can only be accessed by using a unique key, which must be specified when declaring the table. A hashed table has no index, and the response time for key access is constant, regardless of the table size.
References: Internal Tables - ABAP Keyword Documentation, SAP ABAP: Types Of Internal Table Declaration - dan852.com


NEW QUESTION # 24
Which of the following actions cause an indirect change to a database table requiring a table conversion? Note:
There are 2 correct answers to this question.

  • A. Renaming a field in a structure that is included in the table definition
  • B. Changing the field labels of a data element that is used in the table definition.
  • C. Shortening the length of a domain used in a data element that is used in the table definition.
  • D. Deleting a field from a structure that is included in the table definition.

Answer: A,D

Explanation:
Explanation
The following are the explanations for each action:
A: Renaming a field in a structure that is included in the table definition causes an indirect change to the database table, as the field name in the table is derived from the structure. This change requires a table conversion, as the existing data in the table must be copied to a new table with the new field name, and the old table must be deleted.
B: Changing the field labels of a data element that is used in the table definition does not cause an indirect change to the database table, as the field labels are only used for documentation and display purposes. This change does not require a table conversion, as the existing data in the table is not affected by the change.
C: Deleting a field from a structure that is included in the table definition causes an indirect change to the database table, as the field is removed from the table as well. This change requires a table conversion, as the existing data in the table must be copied to a new table without the deleted field, and the old table must be deleted.
D: Shortening the length of a domain used in a data element that is used in the table definition causes an indirect change to the database table, as the field length in the table is derived from the domain. This change requires a table conversion, as the existing data in the table must be checked for compatibility with the new field length, and any data that exceeds the new length must be truncated or rejected.
References: Converting Database Tables - ABAP Keyword Documentation, Adjustment of Database Structures - ABAP Keyword Documentation


NEW QUESTION # 25
Which function call returns 0?

  • A. Count_any_of ( val - 'ABAP ABAP abap' sub "AB" )
  • B. find_any_not_of( val 'ABAP ABAP abap' sub = 'AB')
  • C. Count (val - 'ABAP ABAP abap' sub - 'AB' )
  • D. find_any_of (val = "ABAP ABAP abap' sub = "AB")

Answer: B

Explanation:
The function find_any_not_of returns the position of the first character in the string val that is not contained in the string sub. If no such character is found, the function returns 0. In this case, the string val contains only the characters A, B, and a, which are all contained in the string sub, so the function returns 0. The other functions return positive values, as follows:
Count_any_of returns the number of occurrences of any character in the string sub within the string val. In this case, it returns 8, since there are 8 A's and B's in val.
Count returns the number of occurrences of the string sub within the string val. In this case, it returns 2, since there are 2 AB's in val.
find_any_of returns the position of the first character in the string val that is contained in the string sub. In this case, it returns 1, since the first character A is in sub. Reference: String Functions - ABAP Keyword Documentation, Examples of String Functions - ABAP Keyword Documentation


NEW QUESTION # 26
In ABAP SQL, which of the following can be assigned an alias? Note: There are 2 correct answers to this question.

  • A. order criterion (from order by clause)
  • B. field (from field list)
  • C. database table
  • D. group criterion (from group by clause)

Answer: B,C

Explanation:
In ABAP SQL, an alias is a temporary name that can be assigned to a field or a database table in a query. An alias can be used to make the query more readable, to avoid name conflicts, or to access fields or tables with long names. An alias is created with the AS keyword and is only valid for the duration of the query1.
The following are examples of how to assign an alias to a field or a database table in ABAP SQL:
B) field (from field list): A field is a column of a table or a view that contains data of a certain type. A field can be assigned an alias in the field list of a SELECT statement, which specifies the fields that are selected from the data source. For example, the following query assigns the alias name to the field carrname of the table scarr:
SELECT carrid, carrname AS name FROM scarr.
The alias name can be used instead of carrname in other clauses of the query, such as WHERE, GROUP BY, ORDER BY, and so on2.
C) database table: A database table is a collection of data that is organized in rows and columns. A database table can be assigned an alias in the FROM clause of a SELECT statement, which specifies the data source that is selected from. For example, the following query assigns the alias c to the table scarr:
SELECT c.carrid, c.carrname FROM scarr AS c.
The alias c can be used instead of scarr in other clauses of the query, such as WHERE, JOIN, GROUP BY, ORDER BY, and so on3.
The following are not valid for assigning an alias in ABAP SQL:
A) order criterion (from order by clause): An order criterion is a field or an expression that is used to sort the result set of a query in ascending or descending order. An order criterion cannot be assigned an alias in the ORDER BY clause of a SELECT statement, because the alias is not visible in this clause. The alias can only be used in the clauses that follow the clause where it is defined1.
D) group criterion (from group by clause): A group criterion is a field or an expression that is used to group the result set of a query into subsets that share the same values. A group criterion cannot be assigned an alias in the GROUP BY clause of a SELECT statement, because the alias is not visible in this clause. The alias can only be used in the clauses that follow the clause where it is defined1.


NEW QUESTION # 27
Which ABAP SQL clause allows the use of inline declarations?

  • A. FROM
  • B. FIELDS
  • C. INTO CORRESPONDING FIELDS OF
  • D. INTO

Answer: D

Explanation:
The ABAP SQL clause that allows the use of inline declarations is the INTO clause. The INTO clause is used to specify the target variable or field symbol where the result of the SQL query is stored. The INTO clause can use inline declarations to declare the target variable or field symbol at the same position where it is used, without using a separate DATA or FIELD-SYMBOLS statement. The inline declaration is performed using the DATA or @DATA operators in the declaration expression12. For example:
The following code snippet uses the INTO clause with an inline declaration to declare a local variable itab and store the result of the SELECT query into it:
SELECT * FROM scarr INTO TABLE @DATA (itab).
The following code snippet uses the INTO clause with an inline declaration to declare a field symbol <fs> and store the result of the SELECT query into it:
SELECT SINGLE * FROM scarr INTO @<fs>.
You cannot do any of the following:
FROM: The FROM clause is used to specify the data source of the SQL query, such as a table, a view, or a join expression. The FROM clause does not allow the use of inline declarations12.
INTO CORRESPONDING FIELDS OF: The INTO CORRESPONDING FIELDS OF clause is used to specify the target structure or table where the result of the SQL query is stored. The INTO CORRESPONDING FIELDS OF clause does not allow the use of inline declarations. The target structure or table must be declared beforehand using a DATA or FIELD-SYMBOLS statement12.
FIELDS: The FIELDS clause is used to specify the columns or expressions that are selected from the data source of the SQL query. The FIELDS clause does not allow the use of inline declarations. The FIELDS clause must be followed by an INTO clause that specifies the target variable or field symbol where the result is stored12.


NEW QUESTION # 28

What are valid statements? Note: There are 3 correct answers to this question

  • A. In class CL2, the interface method is named ifl-ml.
  • B. In class CL1, the interface method is named if-ml.
  • C. Class CL2 uses the interface.
  • D. Class CL1 uses the interface.
  • E. Class CL1 implements the interface.

Answer: A,D,E

Explanation:
Explanation
The following are the explanations for each statement:
C: This statement is valid. Class CL1 uses the interface. This is because class CL1 implements the interface ifl using the INTERFACES statement in the public section of the class definition. The INTERFACES statement makes the class compatible with the interface and inherits all the components of the interface. The class can then use the interface components, such as the method ml, by using the interface component selector ~, such as ifl~ml12 E: This statement is valid. Class CL1 implements the interface. This is because class CL1 implements the interface ifl using the INTERFACES statement in the public section of the class definition. The INTERFACES statement makes the class compatible with the interface and inherits all the components of the interface. The class must then provide an implementation for the interface method ml in the implementation part of the class, unless the method is declared as optional or abstract12 D: This statement is valid. In class CL2, the interface method is named ifl~ml. This is because class CL2 has a data member named m0_ifl of type REF TO ifl, which is a reference to the interface ifl. The interface ifl defines a method ml, which can be called using the reference variable m0_ifl. The interface method ml has the name ifl~ml in the class, where ifl is the name of the interface and the character ~ is the interface component selector12 The other statements are not valid, as they have syntax errors or logical errors. These statements are:
A: This statement is not valid. In class CL1, the interface method is named ifl~ml, not if-ml. This is because class CL1 implements the interface ifl using the INTERFACES statement in the public section of the class definition. The interface ifl defines a method ml, which can be called using the class name or a reference to the class. The interface method ml has the name ifl~ml in the class, where ifl is the name of the interface and the character ~ is the interface component selector. Using the character - instead of the character ~ will cause a syntax error12 B: This statement is not valid. Class CL2 does not use the interface, but only has a reference to the interface. This is because class CL2 has a data member named m0_ifl of type REF TO ifl, which is a reference to the interface ifl. The interface ifl defines a method ml, which can be called using the reference variable m0_ifl. However, class CL2 does not implement the interface ifl, nor does it inherit the interface components. Therefore, class CL2 does not use the interface, but only references the interface12 References: INTERFACES - ABAP Keyword Documentation, CLASS - ABAP Keyword Documentation


NEW QUESTION # 29
Which type of legacy code does SAP recommend you eliminate when you review modifications as part of an SAP S/4HANA system conversion? Note: There are 2 correct answers to this question.

  • A. Code that now is identical to a standard SAP object
  • B. Code that supports a critical business process
  • C. Code that can be redesigned as a key user extension
  • D. Code that has less than 10% usage according to usage statistics

Answer: A,C

Explanation:
SAP recommends that you eliminate the following types of legacy code when you review modifications as part of an SAP S/4HANA system conversion:
Code that now is identical to a standard SAP object. This type of code is redundant and unnecessary, as it does not provide any additional functionality or customization. It can also cause conflicts or errors during the system conversion, as the standard SAP object may have changed or been replaced in SAP S/4HANA. Therefore, you should delete this type of code and use the standard SAP object instead.
Code that can be redesigned as a key user extension. This type of code is usually related to UI or business logic adaptations that can be achieved using the in-app tools provided by SAP S/4HANA. By redesigning this type of code as a key user extension, you can simplify and standardize your code base, reduce maintenance efforts, and avoid compatibility issues during the system conversion. Therefore, you should migrate this type of code to the key user extensibility framework and delete the original code.
The other types of legacy code are not recommended to be eliminated, as they may still be relevant or necessary for your business processes. However, you should still review and adjust them according to the SAP S/4HANA simplification items and best practices. These types of code are:
Code that supports a critical business process. This type of code is essential for your business operations and cannot be easily replaced or removed. However, you should check if this type of code is compatible with SAP S/4HANA, and if not, you should adapt it accordingly. You should also consider if this type of code can be optimized or enhanced using the new features and capabilities of SAP S/4HANA.
Code that has less than 10% usage according to usage statistics. This type of code is rarely used and may not be worth maintaining or converting. However, you should not delete this type of code without verifying its relevance and impact on your business processes. You should also consider if this type of code can be replaced or consolidated with other code that has higher usage or better performance.


NEW QUESTION # 30

Which of the following types are permitted to be used for <source> on line #4? Note: There are 2 correct answers to this question.

  • A. A database view from the ABAP Dictionary
  • B. A database table from the ABAP Dictionary
  • C. An external view from the ABAP Dictionary
  • D. A CDS DDIC-based view

Answer: B,D

Explanation:
Explanation
The <source> clause in the CDS View Entity Data Definition can be used to specify the data source for the view entity. The <source> clause can accept different types of data sources, depending on the type of the view entity1.
A database table from the ABAP Dictionary: This is a valid type of data source for a CDS View Entity Data Definition. A database table from the ABAP Dictionary is a table that is defined in the ABAP Dictionary using the keyword TABLE or TABLE OF. The name of the database table must be unique within its namespace and must not contain any special characters2.
A CDS DDIC-based view: This is also a valid type of data source for a CDS View Entity Data Definition. A CDS DDIC-based view is a view that is defined in the Core Data Services using the keyword DEFINE VIEW ENTITY. The name of the CDS DDIC-based view must be unique within its namespace and must not contain any special characters3.
You cannot do any of the following:
An external view from the ABAP Dictionary: This is not a valid type of data source for a CDS View Entity Data Definition. An external view from the ABAP Dictionary is a view that is defined in an external application using any language supported by SAP, such as SQL, PL/SQL, or Java. The name of the external view must be unique within its namespace and must not contain any special characters4.
A database view from the ABAP Dictionary: This is not a valid type of data source for a CDS View Entity Data Definition. A database view from the ABAP Dictionary is a view that is defined in an external application using any language supported by SAP, such as SQL, PL/SQL, or Java. The name of the database view must be unique within its namespace and must not contain any special characters4.
References: 1: CDS DDL - DEFINE VIEW ENTITY - ABAP Keyword Documentation - SAP Online Help 2:
ABAP Dictionary Tables - SAP Online Help 3: CDS DDL - DEFINE VIEW ENTITY - ABAP Keyword Documentation - SAP Online Help 4: ABAP Dictionary Views - SAP Online Help


NEW QUESTION # 31
Why would you use Access Controls with CDS Views? Note: There are 2 correct answers to this question.

  • A. You do not have to remember to implement AUTHORITY CHECK statements.
  • B. All of the data from the data sources is loaded into your application automatically and filtered there according to the user's authorization.
  • C. Only the data corresponding to the user's authorization is transferred from the database to the application layer.
  • D. The system field sy-subrc is set, giving you the result of the authorization check

Answer: A,C

Explanation:
You would use Access Controls with CDS Views for the following reasons:
A) Only the data corresponding to the user's authorization is transferred from the database to the application layer. This is true because Access Controls allow you to define CDS roles that specify the authorization conditions for accessing a CDS view. The CDS roles are evaluated for every user at runtime and the system automatically adds the restrictions to the selection conditions of the CDS view. This ensures that only the data that the user is authorized to see is read from the database and transferred to the application layer. This improves the security and the performance of the data access1.
C) You do not have to remember to implement AUTHORITY CHECK statements. This is true because Access Controls provide a declarative and centralized way of defining the authorization logic for a CDS view. You do not have to write any procedural code or use the AUTHORITY CHECK statement to check the user's authorization for each data source or field. The system handles the authorization check automatically and transparently for you2.
The following reasons are not valid for using Access Controls with CDS Views:
B) The system field sy-subrc is set, giving you the result of the authorization check. This is false because the system field sy-subrc is not used by Access Controls. The sy-subrc field is used by the AUTHORITY CHECK statement to indicate the result of the authorization check, but Access Controls do not use this statement. Instead, Access Controls use CDS roles to filter the data according to the user's authorization2.
D) All of the data from the data sources is loaded into your application automatically and filtered there according to the user's authorization. This is false because Access Controls do not load all the data from the data sources into the application layer. Access Controls filter the data at the database layer, where the data resides, and only transfer the data that the user is authorized to see to the application layer. This reduces the data transfer and the memory consumption of the application layer1.


NEW QUESTION # 32
Exhibit:

With Icl_super being superclass for Icl_subl and Icl_sub2 and with methods subl_methl and sub2_methl being subclass-specific methods of Id_subl or Icl_sub2, respectivel. What will happen when executing these casts? Note:
There are 2 correct answers to this question

  • A. go_sub2 = CAST #(go_super). will not work. ] go sub2->sub2 meth 1(...). will work
  • B. go_subl->subl_meth !(...)* w'll work.
  • C. go_sub2 = CAST # go super), will work. go_subl CAST #go_super), will work
  • D. go subl = CAST # go super), will not work

Answer: B,D

Explanation:
The following are the explanations for each statement:
A: This statement is correct. go_subl = CAST #(go_super) will not work. This is because go_subl is a data object of type REF TO cl_subl, which is a reference to the subclass cl_subl. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_subl, but this is not possible, as go_super is not pointing to an instance of cl_subl, but to an instance of cl_super. Therefore, the CAST operator will raise an exception CX_SY_MOVE_CAST_ERROR at runtime12 B: This statement is incorrect. go_sub2 = CAST #(go_super) will work. go_subl = CAST #(go_super) will not work. This is because go_sub2 is a data object of type REF TO cl_sub2, which is a reference to the subclass cl_sub2. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_sub2, and this is possible, as go_super is pointing to an instance of cl_sub2, which is a subclass of cl_super. Therefore, the CAST operator will assign the reference of go_super to go_sub2 without raising an exception. However, the CAST operator will not work for go_subl, as explained in statement A12 C: This statement is incorrect. go_sub2 = CAST #(go_super) will work. go_sub2->sub2_meth1(...) will not work. This is because go_sub2 is a data object of type REF TO cl_sub2, which is a reference to the subclass cl_sub2. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_sub2, and this is possible, as go_super is pointing to an instance of cl_sub2, which is a subclass of cl_super. Therefore, the CAST operator will assign the reference of go_super to go_sub2 without raising an exception. However, the method call go_sub2->sub2_meth1(...) will not work, as sub2_meth1 is a subclass-specific method of cl_sub2, which is not inherited by cl_super. Therefore, the method call will raise an exception CX_SY_DYN_CALL_ILLEGAL_METHOD at runtime123 D: This statement is correct. go_subl->subl_meth1(...) will work. This is because go_subl is a data object of type REF TO cl_subl, which is a reference to the subclass cl_subl. subl_meth1 is a subclass-specific method of cl_subl, which is not inherited by cl_super. Therefore, the method call go_subl->subl_meth1(...) will work, as go_subl is pointing to an instance of cl_subl, which has the method subl_meth1123


NEW QUESTION # 33
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